Question 1019239: a father is 27 years older than his son. Ten years from now the father will be twice as old as his son. How old is each now? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi there,
a father is 27 years older than his son
F = 27 + S
Ten years from now the father will be
twice as old as his son.
F + 10 = 2(S + 10)
Replace F with (27 + S) from top equation.
27 + S + 10 = 2S + 20
Collect like terms
S - 2S = 20 - 27 - 10
-S = -17
S = 17
Son is 17 years old
Father is 44 years old
Hope this helps :-)
