SOLUTION: School held a Easter play that had a total of 260 students and adults attend the play. Tickets for the play cost $2/student and $5/adult for the play and a total of $1054 was colle

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: School held a Easter play that had a total of 260 students and adults attend the play. Tickets for the play cost $2/student and $5/adult for the play and a total of $1054 was colle      Log On


   

Question 1019193: School held a Easter play that had a total of 260 students and adults attend the play. Tickets for the play cost $2/student and $5/adult for the play and a total of $1054 was collected for the play. State two equations for the problem and define the variables.
Answer by addingup(3677) About Me  (Show Source):
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s+a = 260 subtract s from both and you get: a = 260-s
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2s+5a = 1054 Substitute for a:
2s+5(260-s) = 1054
2s+1300-5s = 1054
-3s = -246 Divide both sides by -3 and remember -/- = +
s = 82 students and
260-82 = 178 adults
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Check:
82*2 = 164
178*5= 890
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Total: 1054 we have the correct answer