SOLUTION: A shopkeeper had 410 sweets. He put some on them into 15 packets containing 12 sweets each. He then put the rest into 24 packets, each containing the same number of sweets. A. Ho

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A shopkeeper had 410 sweets. He put some on them into 15 packets containing 12 sweets each. He then put the rest into 24 packets, each containing the same number of sweets. A. Ho      Log On


   

Question 1018974: A shopkeeper had 410 sweets. He put some on them into 15 packets containing 12 sweets each. He then put the rest into 24 packets, each containing the same number of sweets. A. How many sweets would there be in each of the 14 packets? B. How many sweets were left?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Study of the problem should account for the 410 "sweets". 
pack size       packs       pieces of sweets
    12           15              180
    x            24              24x
TOTAL                            410


highlight_green%28180%2B24x=410%29
24x=410-180
24x=230
x=230%2F24------------Unless this study of the problem has a mistake or misunderstanding, your two questions are bad and the problem description is wrong. You must expect x to be a WHOLE number.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

A shopkeeper had 410 sweets. He put some on them into 15 packets containing 12 sweets each. He then put the rest into 24 packets, each containing the same number of sweets. A. How many sweets would there be in each of the 14 packets? B. How many sweets were left?
How does 14 packets come into the "picture?" 

If it's actually 24 packets, as you stated prior, then highlight_green%28matrix%281%2C5%2C9%2C+were%2C+in%2C+each%2C+packet%29%29, and highlight_green%28matrix%281%2C3%2C14%2C+were%2C+left%29%29