SOLUTION: The length of a rectangle is 7 inches greater than the width. The perimeter is 114 inches. Find the length and width. I have no idea how to solve this.

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Question 1018944: The length of a rectangle is 7 inches greater than the width. The perimeter is 114 inches. Find the length and width.
I have no idea how to solve this.
Found 2 solutions by FrankM, stanbon:
Answer by FrankM(1040) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter is the total of 2 lengths and 2 widths
So length and width add to 57 inches.
L+W=57
But we know L=W+7 so
W+7+W=57
2W+7=57
2W=50
W=25
L=32

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is 7 inches greater than the width.
The perimeter is 114 inches. Find the length and width.
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width:: w
length:: w+7
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P = 2(length+width)
114 = 2(2w+7)
57 = 2w+7
2w = 50
w = 25 inches (width)
w+7 = 32 inches (length)
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Cheers,
Stan H.
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