SOLUTION: Use grouping to factor 10ax-5ay+2bx-by. Explain each step please!

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Question 1018787: Use grouping to factor 10ax-5ay+2bx-by. Explain each step please!
Found 2 solutions by ikleyn, fractalier:
Answer by ikleyn(52834) About Me  (Show Source):
You can put this solution on YOUR website!
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Use grouping to factor 10ax-5ay+2bx-by. Explain each step please!
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10ax - 5ay + 2bx - by = (10ax - 5ay) + (2bx - by) = 5a*(2x-y) + b*(2x-y) = (5a+b)*(2x-y).



Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Okay from
10ax - 5ay + 2bx - by
Do you notice that the first two terms have a common factor? And that it is 5a? We factor that out and get
5a(2x - y) + 2bx - by
Do you see how the 3rd and 4th terms have b in common? We factor the b out...
5a(2x - y) + b(2x - y)
Now, do you see how both terms have (2x - y) in common? We factor that out...
(2x - y)(5a + b)
and we are done.