SOLUTION: How do you solve {{{(2n^2-9n+4)/(2n^2-n)}}}*{{{(n^3)/(n-4)}}}

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: How do you solve {{{(2n^2-9n+4)/(2n^2-n)}}}*{{{(n^3)/(n-4)}}}      Log On


   

Question 101876: How do you solve
%282n%5E2-9n%2B4%29%2F%282n%5E2-n%29*%28n%5E3%29%2F%28n-4%29
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
How do you solve
%282n%5E2-9n%2B4%29%2F%282n%5E2-n%29*%28n%5E3%29%2F%28n-4%29
:
Factor what you can:
%28%282n-1%29%28n-4%29%29%2F%28n%282n-1%29%29 *%28n%5E3%29%2F%28n-4%29
:
Look at it now. that (n-4) & (2n-1) cancels, jumps out at you. Also n into n^3, results:
n%5E2 is the final answer