Question 1018750: How do you graph y-4=2(x-1)? I am not that good in math in graphing. Please help me!
Found 3 solutions by rothauserc, Cromlix, MathTherapy:
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! y - 4 = 2(x - 1)
:
: we first arrange this equation into the slope - intercept form
:
: add 4 to both sides of =
y = 2(x - 1) + 4
: now multiply the terms within parenthesis by 2
y = 2x -2 +4
: combine like terms
y = 2x + 2
: this form tells us that the slope(m) of the line is 2 and that the line intercepts the y axis at (0, 2)
:
here is the graph
Answer by Cromlix(4381)  (Show Source):
You can put this solution on YOUR website! Hi there,
First of all work out equation
into the y = mx + c format.
y-4=2(x-1)
Multiply out brackets
y - 4 = 2x - 2
y = 2x - 2 + 4
y = 2x + 2
Next set up a range of values for 'x'
to obtain values for 'y'
Lets say x = -3, -2, -1, 0, 1, 2, 3,
Substitute each of the 'x' values
into the equation to find 'y'
x = -3
y = 2x + 2
y = 2(-3) + 2
y = -6 + 2
y = -4
Set of points to be graphed (-3,-4)
x = -2
y = 2x + 2
y = 2(-2) + 2
y = -4 + 2
y = -2
set of points to be graphed (-2,-2)
x = -1
y = 2x + 2
y = 2(-1) + 2
y = -2 + 2 = 0
set of points to be graphed (-1,0)
x = 0
y = 2x + 2
y = 2(0) + 2
set of points to be graphed (0,2)
x = 1
y = 2x + 2
y = 2(1) + 2
y = 2 + 2
y = 4
set of points to be graphed (1,4)
x = 2
y = 2x + 2
y = 2(2) + 2
y = 4 + 2
y = 6
x = 3
y = 2x + 2
y = 2(3) + 2
y = 6 + 2
y = 8
set of points to be graphed (3,8)
Plot these points on graph paper
and you will have part of the equation
y = 2x + 2 -3
Hope this helps :-)
Answer by MathTherapy(10555)  (Show Source):
You can put this solution on YOUR website!
How do you graph y-4=2(x-1)? I am not that good in math in graphing. Please help me!
1) Solve the equation for y
2) Substitute 0 for x, and solve for y to determine the y-intercept point
3) Substitute 0 for y, and solve for x to determine the x-intercept point
4) Join the points to get the graph
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