SOLUTION: find four consecutive odd intergers such that the sum of the second and the fourth is 17 more than one half the sum of the first and the third

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Question 1018748: find four consecutive odd intergers such that the sum of the second and the fourth is 17 more than one half the sum of the first and the third
Answer by CubeyThePenguin(3113) About Me  (Show Source):
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4 consecutive odd integers: x, (x+2), (x+4), (x+6)

(x+2) + (x+6) = 17 + 1/2 * (x + (x+4))
2x + 8 = 17 + x + 2
x = 11

The integers are 11, 13, 15, and 17.