SOLUTION: Find four consecutive intergers such that the sum of the second and the forth is four more than twice the first.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find four consecutive intergers such that the sum of the second and the forth is four more than twice the first.      Log On


   

Question 1018746: Find four consecutive intergers such that the sum of the second and the forth is four more than twice the first.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive integers: x, (x+1), (x+2), (x+3)

(x+1) + (x+3) = 2x + 4
2x + 4 = 2x + 4

For any value of x (for any integer), the sum of the second and fourth numbers is four more than twice the first.