SOLUTION: I have seven digits. My first two digits make a multiple of 6 and 9 which is less than 30. My third and fifth digits are place keepers. My last two digits are a multiple of 11 a

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Question 1018725: I have seven digits. My first two digits make a multiple of
6 and 9 which is less than 30. My third and fifth digits are
place keepers. My last two digits are a multiple of 11 and
are said to be lucky numbers. The sum of the numbers is 28.
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
I have seven digits. 
Represent the seven digits by dashes:

-------

My first two digits make a multiple of 6 and 9 
The 2-digit multiples of 6 that are less than 30
are 12, 18, and 24.

The 2-digit multiples of 9 that are less than 30
are 18 and 27.

What is the only one that is both? Put it where
the letters AB are

AB-----

My third and fifth digits are place keepers. 
What is the place keeping digit?  Hint: It is oval-shaped
and looks like one of the round letters of the alphabet.
When spelled, it starts with the last letter of the alphabet.
Put that same number 3rd and 5th where the two letters C are.

ABC-C--

My last two digits are a multiple of 11 and are said to be
lucky numbers.
Do you know which digit that is said to be the lucky number? 

If not go to this site:

https://in.answers.yahoo.com/question/index?qid=20070302051653AA9tAbv

Write it where the D's are

ABC-CDD

The sum of the numbers is 28
Add the numbers A+B+C+C+D+D

Then subtract what you get from 28.  That should have just one
digit.

Place it where the E is:

ABCECDD

Now you will have the answer.

Edwin