SOLUTION: The period of a pendulum is equal to 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity. If the length of the pendulum is 40 m and

Algebra ->  Expressions-with-variables -> SOLUTION: The period of a pendulum is equal to 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity. If the length of the pendulum is 40 m and       Log On


   

Question 1018714: The period of a pendulum is equal to 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity. If the length of the pendulum is 40 m and the acceleration due to gravity is 10 m/s^2, what is the period of the pendulum?
Answer by ikleyn(52873) About Me  (Show Source):
You can put this solution on YOUR website!
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The period of a pendulum is equal to 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity.
If the length of the pendulum is 40 m and the acceleration due to gravity is 10 m/s^2, what is the period of the pendulum?
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T = 2%2Api%2Asqrt%28L%2Fg%29 = 2%2A3.14%2Asqrt%2840%2F10%29 = 2*3.14*2 = . . . (?)

Please calculate it yourself.