SOLUTION: find the points of intersection of the parabolas x^2+2x+3y+4= and x^2-3x+y+3=0

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Question 1018683: find the points of intersection of the parabolas x^2+2x+3y+4= and x^2-3x+y+3=0
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Solve each equation for y in terms of x.
system%28y=-%281%2F3%29%28x%5E2%2B2x%2B4%29%2Cy=-%28x%5E2-3x%2B3%29%29

Equate the expressions of x and simplify:
highlight_green%282x%5E2-11x%2B5=0%29
which is factorable:
%282x-1%29%28x-5%29=0

system%28x=1%2F2%2COR%2Cx=5%29
Find the corresponding y coordinates for each.

You can fill-in all the steps not shown and also to finish.

Answer by ikleyn(52803) About Me  (Show Source):