SOLUTION: Find two consecutive integers such that the larger is nine more than twice the smaller

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Question 1018609: Find two consecutive integers such that the larger is nine more than twice the smaller
Answer by toddcarnes(6) About Me  (Show Source):
You can put this solution on YOUR website!
Question: Find two consecutive integers such that the larger is nine more than twice the smaller.
Answer:
Let x be your first integer.
Then x + 1 will be the next consecutive integer.
Create the equation given in the original problem...
(x+1) = 2x + 9
Solve for x...
x + 1 = 2x + 9
1 = x + 9
x = -8
If x = -8, then (x+1) = -7.
Therefore the two consecutive integers you are looking for are -8 and -7.