SOLUTION: what is the probability of drawing 3 clubs or a six of diamonds?

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Question 101853: what is the probability of drawing 3 clubs or a six of diamonds?
Found 2 solutions by stanbon, Fombitz:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
what is the probability of drawing 3 clubs or a six of diamonds?
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Those are mutually exclusive events so
P(3 clubs or six of diamonds) = P(3clubs)+P(6 of diamonds)
= 13C3/52C3 + 1/52
= 286/22100 + 1/52
= 0.13 + 0.19
= 0.32
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Cheers,
Stan H.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming you mean a standard 52 card deck and your question is the probability of drawing either a 3 ClubsP%5B1%5D or 6 Diamonds P%5B2%5Don one draw. The probability of drawing a 3 Clubs alone and the probability of drawing a 6 Diamonds alone are both equalP%5B1%5D=P%5B2%5D=1%2F52. By putting them together, you add their probabilities. So the probability of drawing either a 3 Clubs or 6 Diamonds on one draw is 2/52P%5B3%5D=1%2F52%2B1%2F52=2%2F52.