SOLUTION: I cannot figure the correct term terms to use. Help please. During the winter months, Mr Myer experiences diffuculty in staring his 2 cars, a 1966 Mustang and a 1986 Ranger. The p

Algebra ->  Probability-and-statistics -> SOLUTION: I cannot figure the correct term terms to use. Help please. During the winter months, Mr Myer experiences diffuculty in staring his 2 cars, a 1966 Mustang and a 1986 Ranger. The p      Log On


   



Question 101848: I cannot figure the correct term terms to use. Help please.
During the winter months, Mr Myer experiences diffuculty in staring his 2 cars, a 1966 Mustang and a 1986 Ranger. The probability that the Mustang starts in 0.8, and the probablity the Ranger starts is .4. The probability that both cars start is 0.3. Let A represent the event "The Mustang starts, and B represent "The Ranger Starts". Use probability notation to describe and solve the following:
a. What is the probability that Mr Myer can start at least one of his cars?
b. What is the probability that Mr Myer cannot start either of his cars?
Wow it seems like a lot to. Should I start with a joint probability table?
I can say A is Mustang Starts=.8 So A' prime will be .2? To equal 1
I can say B is Ranger Starts=.4 So B' prime will be .6? To equal 1
What do I do with the both cars start information? Which is 0.3. Would I need a C and a C' prime? How do I write this probability notation?
Thank you for your assistance.

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
a. What is the probability that Mr Myer can start at least one of his cars?
.2=chance that mustang wont start
.6=chance that ranger wont start
.2*.6=.12 chance neither starts (answer to part b)
1-.12=.88 probability at least one of his cars start.
.
b. What is the probability that Mr Myer cannot start either of his cars?
.2*.6=.12 chance neither starts
Ed