SOLUTION: Find three consecutive even integers such that the sum of twice the first, four times the second, and three times the third is 398

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Question 1018435: Find three consecutive even integers such that the sum of twice the first, four times the second, and three times the third is 398
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
3 consecutive even integers
n, n + 2 and n + 4.
2(n) + 4(n + 2) + 3(n + 4) = 398
2n + 4n + 8 + 3n + 12 = 398
Collect like terms
2n + 4n + 3n + 398 - 8 - 12
9n = 378
n = 42
42, 44, 46
Proof:
2(42) + 4(44) + 3(46) = 398
Hope this helps :-)