SOLUTION: A family goes on vacation to a water park. During the drive there they averaged 48mph. On the return trip they averaged 80mph. If the distance each way was equal, and the whole

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Question 1018269: A family goes on vacation to a water park. During the drive there they averaged 48mph. On the return trip they averaged 80mph. If the distance each way was equal, and the whole trip driving was 6.4 hours, find the distance ONE WAY to the water park.
Found 2 solutions by josgarithmetic, stanbon:
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
Travel Rates Rule, RT=D 

                  rate         time        distance
GOING              48          d/48           d
BACK               80          d/80           d
Total                           6.4

Clear enough what to do


d=192

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A family goes on vacation to a water park. During the drive there they averaged 48mph. On the return trip they averaged 80mph. If the distance each way was equal, and the whole trip driving was 6.4 hours, find the distance ONE WAY to the water park.
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To the park DATA:
dist = x mph ; rate = 48mph ; time = d/r = x/48 hrs
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From the park DATA:
dist = x mph ; rate = 80 mph ; time = x/80 hrs
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Equation:
time + time = 6.4 hrs
x/48 + x/80 = 6.4
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80x + 48x = 6.4*80*48
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128x = 24976
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x = distance = 192 miles
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Cheers,
Stan H.
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