SOLUTION: How would I graph the following equation and state the axes of symmetry Y=2x2-4x-2

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Question 1018253: How would I graph the following equation and state the axes of symmetry
Y=2x2-4x-2
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
y=2x%5E2-4x-2 is not factorable. You can change into standard form and read the vertex and also find the zeros (or x-axis intercepts) by equating y=0.

graph%28300%2C300%2C-6%2C6%2C-6%2C6%2C2x%5E2-4x-2%29

Also you could just use the general solution formula for a quadratic equation.
2%28x%5E2-2x-1%29=0
x%5E2-2x-1=0
x=%282%2B-+sqrt%28%28-4%29%5E2-4%2A%28-1%29%29%29%2F2
x=%282%2B-+sqrt%2820%29%29%2F2
x=%282%2B-+2sqrt%285%29%29%2F2
highlight%28x=1%2B-+sqrt%285%29%29-------the x-axis intercepts, therefore the vertex and symmetry axis are quickly and easily found.