SOLUTION: Find two solutions of each equation. Give your answers in degrees
(0° ≤ θ < 360°)
and in radians
(0 ≤ θ < 2π).
Do not use a calculator. (Do not e
Algebra ->
Trigonometry-basics
-> SOLUTION: Find two solutions of each equation. Give your answers in degrees
(0° ≤ θ < 360°)
and in radians
(0 ≤ θ < 2π).
Do not use a calculator. (Do not e
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Question 1018145: Find two solutions of each equation. Give your answers in degrees
(0° ≤ θ < 360°)
and in radians
(0 ≤ θ < 2π).
Do not use a calculator. (Do not enter your answers with degree symbols. Enter your answers as comma-separated lists.)
(a)
sec θ =( 2 Sqrt3)/3
Note: The value of cosine is the value of the -coordinate of the intersection of the terminal ray of an angle and the unit circle. Note that there are two points with the desired -coordinate. Multiply radians by to get degrees.
.
John
My calculator said it, I believe it, that settles it
You can put this solution on YOUR website! sec theta=2sqrt (3)/3
cos theta is the inverse or 3/2sqrt(3)
rationalize and 3sqrt(3)/2*3 = sqrt(3)/2.
This is cosine of 60 or cos 330. Those are two solutions in degrees (60,330)
In radians, it is (pi/3 ,11pi/6).
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