Question 101786: The width and length of a rectangle are consecutive odd intergers. If the width is w, fird the perimeter, in simplest form, in terms of w.
for some reason I don't think that there is an answer to this problem. Am i correct or is there an answer?
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! There is an answer.
Consecutive odd integers. So if W=3 then L=5, if W=13, then L=15. So the relationship is Width = W, Length = W+2, where W is an odd integer.
Now the perimeter, P, of a rectangle is twice the width plus twice the length or
P = 2(Width)+2(Length)
Let's substitute with values from above:
P = 2(Width)+2(Length) Substitute for Width and Length in terms of W
P = 2(W)+2(W+2)
P = 2W+2(W)+2(2) Use the distributive property and simplify.
P = 4W+4
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