SOLUTION: I add 5 to a certain number, and then divide by 6. Starting with the same number, I subtract 1 from it, and then divide by 4. If the result is the same in each case, find the numbe

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: I add 5 to a certain number, and then divide by 6. Starting with the same number, I subtract 1 from it, and then divide by 4. If the result is the same in each case, find the numbe      Log On


   

Question 1017807: I add 5 to a certain number, and then divide by 6. Starting with the same number, I subtract 1 from it, and then divide by 4. If the result is the same in each case, find the number.
Found 2 solutions by josgarithmetic, macston:
Answer by josgarithmetic(39620) About Me  (Show Source):
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
x=the number
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%28x%2B5%29%2F6=%28x-1%29%2F4
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4%28x%2B5%29=6%28x-1%29
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4x%2B20=6x-6
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26=2x
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13=x
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ANSWER: The number is 13.
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CHECK:
%28x%2B5%29%2F6=%28x-1%29%2F4
%2813%2B5%29%2F6=%2813-1%29%2F4
18%2F6=12%2F4
3=3