SOLUTION: two numbers have a difference of 11 whilst fives times the smaller exceeds twice the larger by 17. find the two numbers

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Question 1017791: two numbers have a difference of 11 whilst fives times the smaller exceeds twice the larger by 17. find the two numbers
Answer by macston(5194) About Me  (Show Source):
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L=larger number; S=smaller number
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L-S=11
L=S+11
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5S-2L=17
5S-2(S+11)=17
5S-2S-22=17
3S=39
S=13
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L=S+11=13+11=24
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ANSWER: The smaller number is 13 and the larger is 24.
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CHECK:
5S-2L=17
5(13)-2(24)=17
65-48=17
17=17
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