Question 1017712: So in my math problem, I have a right triangle, with 12 on the left side, 8 on the right side, and x-5 on the bottom. How do you solve this?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! So in my math problem, I have a right triangle, with 12 on the left side, 8 on the right side, and x-5 on the bottom. How do you solve this?
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I'm going to assume that x-5 is the hypotenuse.
If so, (x-5)^2 = 12^2 + 8^2
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(x-5)^2 = 144+64
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(x-5)^2 = 208
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x-5 = sqrt(208) = = sqrt(16*13) = 4sqrt(13)
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x = 4sqrt(13)+5
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Cheers,
Stan H.
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