SOLUTION: a rectangular field is 6 times as long as it is wide. if the length is decreased by 4m and the width is increased by 2m, the perimeter will be 52m. find the dimensions of the origi
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Question 1017564: a rectangular field is 6 times as long as it is wide. if the length is decreased by 4m and the width is increased by 2m, the perimeter will be 52m. find the dimensions of the original field Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi there,
a rectangular field is 6 times as long as it is wide
Make the width = x
Length = 6x
if the length is decreased by 4m and the width is
increased by 2m,
Length = 6x - 4 Width = x + 2
the perimeter will be 52m.
Perimeter = 2(Width) + 2(Length)
52 = 2(x + 2) + 2(6x - 4)
52 = 2x + 4 + 12x - 8
Collect like terms
2x + 12x = 52 - 4 + 8
14x = 56
x = 4
Dimensions of original field:
Width = 4m
Length = 24m
Hope this helps :-)
