SOLUTION: A sphere is just fit in a cone such that it is the largest sphere that can be fit into that sphere. The height of cone is 8 cm and radius of cone is 6 cm. Find the volume of the sp

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Question 1017561: A sphere is just fit in a cone such that it is the largest sphere that can be fit into that sphere. The height of cone is 8 cm and radius of cone is 6 cm. Find the volume of the sphere.
Found 3 solutions by Alan3354, ikleyn, Edwin McCravy:
Answer by Alan3354(69443) About Me  (Show Source):
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A sphere is just fit in a cone such that it is the largest sphere that can be fit into that sphere. The height of cone is 8 cm and radius of cone is 6 cm. Find the volume of the sphere.
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Find the radius of the sphere.
Use a triangle with a base of 12 cm and a height of 8 cm.
--> a triangle with sides of 10, 10 & 12 cm.
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There are various ways to find r of the inscribed circle.
r = 3
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V of the sphere = 4pi%2Ar%5E3%2F3 cc

Answer by ikleyn(52815) About Me  (Show Source):
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.
A sphere is just fit in a cone such that it is the largest sphere that can be fit into that sphere. The height of cone is 8 cm and radius of cone is 6 cm. Find the volume of the sphere.
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See the lesson Solved problems on volume of spheres in this site.

Very similar problem was solved there (Problem 5) with detailed explanations.


Answer by Edwin McCravy(20060) About Me  (Show Source):
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Here is a drawing of the mid-cross section of the 
largest sphere in the cone, which is the largest 
circle inside triangle ABC:



Right triangles ADC and OEC are similar because they share
a common angle at A.

The hypotenuse of ADC is AC.  And AC = 10 by the Pythagorean 
theorem applied to triangle ADC. (6²+8²=10²)

%28OC%29%2F%28AC%29%22%22=%22%22OE%2FAD

So:

%288-r%29%2F10%22%22=%22%22r%2F6

Cross-multiply and solve that and get r = 3

So the radius of the circle is 3, which is also the radius of
the sphere.

The volume of a sphere is given by the formula

V%22%22=%22%22expr%284%2F3%29pi%2Ar%5E3

V%22%22=%22%22expr%284%2F3%29pi%2A3%5E3

V%22%22=%22%2236pi cubic centimeters.

Edwin