SOLUTION: Factor help is appreciated 4r^3 - 4r^2 + 2r - 2
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Question 1017425
:
Factor help is appreciated
4r^3 - 4r^2 + 2r - 2
Answer by
fractalier(6550)
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We can factor this one by grouping...
4r^3 - 4r^2 + 2r - 2 = 4r^2(r - 1) + 2(r - 1) = (4r^2 + 2)(r - 1) = 2(2r^2 + 1)(r - 1)
