SOLUTION: Suppose that a cyclist began a 308 mi ride across a state at the western edge of the&#8203; state, at the same time that a car traveling toward it leaves the eastern end of the

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Question 1017401:
Suppose that a cyclist began a 308 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 5.5 hr and the car traveled 36.8 mph faster than the bicycle, find the average rate of each.
The car average rate is ___ mph?
The bicycle's rate is ____ mph?
Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
Let = the speed of the bicycle in mi/hr
= the speed of the car in mi/hr
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You can think of one of them moving at the sum
of their speeds and the other one standing still,
because they are moving towards eachother.
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The distance traveled will be the sum of the
distances each would have traveled
in hrs
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and

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The speed of the bicycle is 9.6 mi/hr
The speed of the car is 46.4 mi/hr
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check answers:
For the bicycle:

For the car:

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OK

SOLUTION: Suppose that a cyclist began a 308 mi ride across a state at the western edge of the&#8203; state, at the same time that a car traveling toward it leaves the eastern end of the

SOLUTION: Suppose that a cyclist began a 308 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the