SOLUTION: I have 2 questions. 1. y^2+2y+5, for y=-6 =29 Why is -6 put into this problem as (-6). Shouldn't it be put in as -6 since -6^2 is different than (-6)^2? 2.ab*ab*

Algebra ->  Exponents -> SOLUTION: I have 2 questions. 1. y^2+2y+5, for y=-6 =29 Why is -6 put into this problem as (-6). Shouldn't it be put in as -6 since -6^2 is different than (-6)^2? 2.ab*ab*      Log On


   



Question 1017365: I have 2 questions.
1. y^2+2y+5, for y=-6
=29 Why is -6 put into this problem as (-6). Shouldn't it be put in as -6 since -6^2 is different than (-6)^2?
2.ab*ab*ab Are a^3b^3 and (ab)^3 compatible solutions or is one wrong?

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
-6%5E2%3C%3E%28-6%29%5E2 That's true.
y%5E2%2B2y%2B6=%28-6%29%5E2%2B2%28-6%29%2B5=36-12%2B5=41-12=29
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a%5E3b%5E3=%28ab%29%5E3 That's also true.