SOLUTION: The instructions are: Solve and check
The original question is:
b^(3/2)=8
My work:
b^(3/2)=8
b^(3/2)^2/3=(8)^2/3
b=sqrt8^3
My problem
There is no perfect square r
Algebra ->
Exponents
-> SOLUTION: The instructions are: Solve and check
The original question is:
b^(3/2)=8
My work:
b^(3/2)=8
b^(3/2)^2/3=(8)^2/3
b=sqrt8^3
My problem
There is no perfect square r
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Question 1017178: The instructions are: Solve and check
The original question is:
b^(3/2)=8
My work:
b^(3/2)=8
b^(3/2)^2/3=(8)^2/3
b=sqrt8^3
My problem
There is no perfect square root of 8 and or 512 (512 is 8^3). Should I just check to see if I get the same thing or is there more work to be done?
Thanks so much in advance...
-Will (10th Grade Algebra II) Found 2 solutions by rothauserc, ikleyn:Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! b^(3/2) means square root of b^3, then
square root of b^3 = 8
:
square both sides of =
:
b^3 = 64
:
b = cube root of 64
:
b = 4
:
check answer
:
square root of 4^3 = 8
:
square root(64) = 8
:
8 = 8
:
our answer checks
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