SOLUTION: I am lost on what to do with is the given data. The question is; Determine the vertex of the parabla: y=(x+2)^2 What is the axis of symmetry? I know the axis of symmetry is h

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I am lost on what to do with is the given data. The question is; Determine the vertex of the parabla: y=(x+2)^2 What is the axis of symmetry? I know the axis of symmetry is h       Log On


   



Question 101712: I am lost on what to do with is the given data. The question is;
Determine the vertex of the parabla: y=(x+2)^2
What is the axis of symmetry?
I know the axis of symmetry is h but how do I find the h?
Thank you for your time

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the vertex of the parabla: y=(x+2)^2
Vertex form is y-k = (x-h)^2
The vertex is at (h,k)
Your Problem:
y-0 = (x-(-2))^2
Vertex is at (-2,0)
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What is the axis of symmetry?
Axis of symmetry is a vertical line thru the vertex.
Axis of symmetry equation: x=-2
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Cheers,
Stan H.