SOLUTION: A man has $0.70 in dimes and nickels. He has 8 coins altogether. How many nickels does he have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: A man has $0.70 in dimes and nickels. He has 8 coins altogether. How many nickels does he have?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1017023: A man has $0.70 in dimes and nickels. He has 8 coins altogether. How many nickels does he have?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
N=nickels; D=dimes
.
N+D=8
N=8-D
.
$0.05N+$0.10D=$0.70
$0.05(8-D)+$0.10D=$0.70
$0.40-$0.05D+$0.10D=$0.70
$0.05D=$0.30
D=6 . There are 6 dimes.
.
N=8-D=8-6=2
.
ANSWER: There are 2 nickels.
.
CHECK:
$0.05N+$0.10D=$0.70
$0.05(2)+$0.10(6)=$0.70
$0.10+$0.60=$0.70
$0.70=$0.70
.