Question 1016902: A man is 32 years older than his son. Ten years ago he was three times older as his Don was then. Find the present age of each. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A man is 32 years older than his son. Ten years ago he was three times older as his Don was then. Find the present age of each.
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M = S + 32
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10 yrs ago:
M = 4S
S+32 = 4S
S = 10 2/3
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Now:
S = 20 yrs 8 months
M = 52 yrs 8 months