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| Question 1016806:  Last year Rachel invested money in two accounts.  The first account had an interest rate of 6% and the second account had an interest rate of 4%.  If she invested $300 more in the first account than the second and her total interest income was $608, how much did she invest at each rate?
 Step 1 of 3 :  Complete the following table by entering the missing values. Enter the rates in decimal for
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Last year Rachel invested money in two accounts. The first account had an interest rate of 6% and the second account had an interest rate of 4%. If she invested $300 more in the first account than the second and her total interest income was $608, how much did she invest at each rate? ----
 Equations:
 s = f + 300 dollars
 0.06s + 0.04f = 608 dollars
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 Modify for elimination::
 6s - 6f = 6*300
 6s + 4f = 100*608
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 Subtract and solve for "f"::
 10f = 59000
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 f = $5900.00 (amt invested at 4%)
 s = f+300 = $59,300 (amt invested at 6%)
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 Cheers,
 Stan H.
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