SOLUTION: a3+5a = 15a2 furthest I got was (a3 = a cubed; 15a2 = 15a squared; a2 = a squared) a3-15a2+ 5a = 0 a(a2 -15a +5) = 0 not sure what to do next?

Algebra ->  Rational-functions -> SOLUTION: a3+5a = 15a2 furthest I got was (a3 = a cubed; 15a2 = 15a squared; a2 = a squared) a3-15a2+ 5a = 0 a(a2 -15a +5) = 0 not sure what to do next?      Log On


   

Question 1016794: a3+5a = 15a2
furthest I got was (a3 = a cubed; 15a2 = 15a squared; a2 = a squared)
a3-15a2+ 5a = 0
a(a2 -15a +5) = 0
not sure what to do next?
Answer by ikleyn(52930) About Me  (Show Source):
You can put this solution on YOUR website!
.
Next apply the quadratic formula.

There is no other options.