SOLUTION: How would this be solved: (x+3/3x) > 2 I think the LCM is 6x but I'm not sure about the excluded values. Thank you

Algebra ->  Rational-functions -> SOLUTION: How would this be solved: (x+3/3x) > 2 I think the LCM is 6x but I'm not sure about the excluded values. Thank you      Log On


   



Question 1016680: How would this be solved: (x+3/3x) > 2
I think the LCM is 6x but I'm not sure about the excluded values. Thank you

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How would this be solved: (x+3/3x) > 2
I think the LCM is 6x but I'm not sure about the excluded values. Thank you
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If you assume that x > 0, x+3 > 6x
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Then 5x < 3
0 < x < 3/5
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If you assume that x < 0, x+3 < 6x
5x > 3
x > 3/5
That contradict x < 0.
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Ans:: So 0< x < 3/5
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Cheers,
Stan H.
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