Question 1016423: The sum of the three smallest of four consecutive odd integers is 30 more than the largest integer. What are the four consecutive odd integers?
Found 2 solutions by macston, fractalier:
Answer by macston(5194)   (Show Source):
You can put this solution on YOUR website! .
F=first integer; S=second integer=F+2; T=third integer=F+4; X=fourth integer=F+6
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F+S+T=X+30
F+(F+2)+(F+4)=(F+6)+30
3F+6=F+36
2F+6=36
2F=30
F=15
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S=F+2=15+2=17
T=F+4=15+4=19
X=F+6=15+6=21
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ANSWER The numbers are 15, 17, 19, and 21.
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CHECK:
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F+S+T=X+30
15+17+19=21+30
51=51
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Answer by fractalier(6550)  (Show Source):
You can put this solution on YOUR website! Call the four consecutive odd numbers x, x+2, x+4, and x+6.
Then we can write
x + x+2 + x+4 = 30 + x+6
3x + 6 = x + 36
2x = 30
x = 15
The numbers are
15,17,19,21
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