SOLUTION: I've trying to figuring out what's wrong with this problem but cant figure it out? t^2-5t=7 Discriminant=(-5)^2-4(1)(7) =25-28 =-3 Discriminant is negative no real

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Question 1016401: I've trying to figuring out what's wrong with this problem but cant figure it out?
t^2-5t=7
Discriminant=(-5)^2-4(1)(7)
=25-28
=-3
Discriminant is negative no real solution.
Found 3 solutions by Boreal, josgarithmetic, fractalier:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
You need to bring the 7 to the other side, and then it will be negative.
t^2+5t-7=0.
Now you can solve.
The discriminant is 53.
x= (1/2) (5 +/- sqrt (53))
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2Cx%5E2-5x-7%29

Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
t%5E2-5t=7
t%5E2-5t-7=0
Discriminant is %28-5%29%5E2-4%2A1%2A%28-7%29=25%2B4%2A7=25%2B28=53, a positive real number. Equation has two real solutions.

t=%285%2B-+sqrt%2853%29%29%2F2

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
The discriminant is found from the quadratic in standard form as b^2 - 4ac.
Let's get this guy in standard form...
t^2 - 5t - 7 = 0
so that
b^2 - 4ac = (-5)^2 - 4(1)(-7) = 25 + 28 = 53
That tells us we have two real roots.