SOLUTION: A chemist has two solutions of H2SO4. One has a 40% concentration and the other has a 25% concentration. How many liters of each solution must be mixed to obtain 128 liters of a 34

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Question 1016395: A chemist has two solutions of H2SO4. One has a 40% concentration and the other has a 25% concentration. How many liters of each solution must be mixed to obtain 128 liters of a 34% solution?
Thank you.
--Will
Found 3 solutions by josgarithmetic, ikleyn, fractalier:
Answer by josgarithmetic(39620)   (Show Source):
You can put this solution on YOUR website!
Very common type of mixture problem

Two variables method taught here for two-part mixture

video example demonstrating how to use just a single variable

Answer by ikleyn(52803)   (Show Source):
You can put this solution on YOUR website!
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A chemist has two solutions of H2SO4. One has a 40% concentration and the other has a 25% concentration. How many liters of each solution must be mixed to obtain 128 liters of a 34% solution?
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See the lesson Solving typical word problems on mixtures for solutions in this site, Problem 1.

This problem is very similar to yours.

Consider it as a sample. Read it attentively.

Then solve your problem by substituting your data.

Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website!
Call the amount of 40% solution, x.
Then the amount of 25% used is 128 - x.
The set up looks like this:
x(.40) + (128-x)(.25) = 128(.34)
.4x + 32 - .25x = 43.52
.15x = 11.52
x = 11.52/.15 = 76.8 liters of 40% solution
128-x = 51.2 L of 25% solution