SOLUTION: cindy has 17 bills in her wallet. some are $10 bills and some are $20 bills. the total value of the bills are $230. how many $10 bills and how many $20 bills does she have?
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Question 1016199: cindy has 17 bills in her wallet. some are $10 bills and some are $20 bills. the total value of the bills are $230. how many $10 bills and how many $20 bills does she have? Found 3 solutions by ikleyn, fractalier, Alan3354:Answer by ikleyn(52775) (Show Source):
You can put this solution on YOUR website! .
cindy has 17 bills in her wallet. some are $10 bills and some are $20 bills. the total value of the bills are $230.
how many $10 bills and how many $20 bills does she have?
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Let x = # of $10 bills, and y = # of $20 bills.
Then you have the system of two equations in two unknowns
x + y = 17, (1)
10x + 20y = 230. (2)
Express x via y from equation (1): x = 17 - y, and substitute it into equation (2). You will get a single equation for y
10*(17-y) + 20y = 230.
Now simplify and solve:
170 - 10y + 20y = 230,
10y = 230 - 170 = 60.
y = = 6.
Then x = 17 - y = 17 - 6 = 11.
Answer. 11 $10 bills and 6 $20 bills.
You can put this solution on YOUR website! Call the number of $10 and $20 bills, x and y. Then we have
x + y = 17 and the value equation is
10x + 20y = 230 Now multiply the top one by ten and subtract and get
-(10x + 10y = 170)
--------------------
10y = 60
y = 6 $20 bills
and then we must have
x = 11 $10 bills
You can put this solution on YOUR website! cindy has 17 bills in her wallet. some are $10 bills and some are $20 bills. the total value of the bills are $230. how many $10 bills and how many $20 bills does she have?
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t = # of 10's
w = # of 20's
--------
t + w = 17
10t + 20w = 230 --> t + 2w = 23
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t + w = 17
t + 2w = 23
---------------- Subtract
-w = -6
--> 6 $20's
11 $10