SOLUTION: A farmer has a rectangular garden plot surrounded by 200 ft of fence. Find the length and width of the garden if its area is 2475 ft^2

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Question 1015954: A farmer has a rectangular garden plot surrounded by 200 ft of fence. Find the length and width of the garden if its area is 2475 ft^2
Found 2 solutions by Boreal, stanbon:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
The width can be x
The length can be 100-x
The perimeter is twice both or 2x+200-2x=200.
The area is x(100-x)=100x-x^2
That equals 2475 sq ft
-x^2+100x-2475=0
x^2-100x+2475=0, multiplying through by -1.
(x-45)(x-55)=0
x=45,55; width is 45 or 55
doesn't matter, because length is 45 or 55. If we make width the smaller, the length and width are 55*45. That gives the area and the perimeter.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A farmer has a rectangular garden plot surrounded by 200 ft of fence. Find the length and width of the garden if its area is 2475 ft^2
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length = L
Width = W
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2(L+W) = 200ft
L+W = 100 ft
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LW = 2475
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Substitute for L and solve for W::
(100-W)W = 2475
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W^2 -100W + 2475 = 0
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W = 45 or W = 55
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Cheers,
Stan H.
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