Question 1015880: Consider the logarithmic equation f(x) = ln (x + 2) – 1. Round all values to the tenths place.
(a) Determine any x- and y-intercepts.
(b) Determine the domain and the equation of the vertical asymptote.
(c) Make a table of values to find three other points on the graph.
(d) Graph the function. Label the three points you found in Part (c).
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! ln(x+2)-1
x must be greater than -2.
As x approaches -2, ln (x+2) gets more and more negative, so x=-2 is vertical asymptote. When x=0, y=ln(2)-1, =-0.3
when y=0,
ln(x+2)=1 and raising both to the e power, (x+2)=2.7 and x=0.7
ln(1)=0, therefore x=-1, y=-1
Table
0,-0.3
0.7,0
-1,-1
|
|
|
