SOLUTION: Six times the smallest of three consecutive odd integers is 28 more than twice the largest. Find the integers

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Question 1015872: Six times the smallest of three consecutive odd integers is 28 more than twice the largest. Find the integers
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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S=smallest integer; M=middle integer=S+2; L=largest integer=S+4
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6S=2L+28
6S=2(S+4)+28
6S=2S+8+28
6S=2S+36
4S=36
S=9
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M=S+2=9+2=11
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L=S+4=9+4=13
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ANSWER: The three integers are 9,11, and 13.
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CHECK:
6S=2L+28
6(9)=2(13)+28
54=26+28
54=54
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