SOLUTION: Factor Completely x^2-2x-4y^2-4y I got x(x-2)-4y(y-1)

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Question 1015802: Factor Completely
x^2-2x-4y^2-4y
I got x(x-2)-4y(y-1)

Found 3 solutions by fractalier, ikleyn, Boreal:
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Let's see...
x^2 - 2x - 4y^2 - 4y = x^2 - 4y^2 - 2x - 4y = (x+2y)(x-2y) - 2(x+2y) =
(x - 2y - 2)(x + 2y)
How's that?

Answer by ikleyn(52802) About Me  (Show Source):
You can put this solution on YOUR website!
.
Factor Completely
x^2-2x-4y^2-4y
------------------------

x%5E2-2x-4y%5E2-4y = %28x%5E2+-+4y%5E2%29 - %282x+%2B+4y%29 = %28x%2B2y%29%2A%28x-2y%29 - 2%2A%28x%2B2y%29 = (x+2y)*(x-2y-2).



Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x(x-2)-4y(y-1)
Expand it to check
x^2-2x-4y^2+4y.
the second part is -4y(y+1)--the minus sign is factored out, so a plus sign stays. When you multiply the -4y by 1, you get back the -4y you need.
x(x-2)-4y(y+1)