Question 1015721: Larry Mitchell invested part of his $21,000 advance at 8% annual simple interest and the rest at 7% annual simple interest. If his total yearly interest from both accounts was $1,580, find the amount invested at each rate.
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! Some at 0.08
Some at 0.07
Total 21,000
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Let's call the investment at 8% x
What's left of the 21,000 is at 7%
So:
0.08 = x
0.07 = 21,000-x
0.08x+0.07(21,000-x) = 1,580
0.08x+1,470-0.07x = 1,580 Subtract x on left and subtract 1,470 on both sides:
0.01x = 110 Divide both sides by 0.01
x = 11,000 is at 8%. And:
21,000-11,000 = 10,000 at 7%
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Check:
0.08*11,000 = 880
0.07*10,000 = 700
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Total... = 1,580 We have the correct answer
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