SOLUTION: Please help me with this problem. I have tried but my answer is incorrect. Show all steps. Thanks in advance Put the equation y=x^2−16x+63 into the form y=(x+h)^2+k:

Algebra ->  Equations -> SOLUTION: Please help me with this problem. I have tried but my answer is incorrect. Show all steps. Thanks in advance Put the equation y=x^2−16x+63 into the form y=(x+h)^2+k:       Log On


   

Question 1015555: Please help me with this problem. I have tried but my answer is incorrect. Show all steps. Thanks in advance


Put the equation y=x^2−16x+63 into the form y=(x+h)^2+k:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
y=x^2−16x+63
The vertex has an x-value of -b/2a=-(-16)/2=8
f(8)= -1
Therefore, the vertex is at (8,-1)
The vertex form is (x+h)^2 +k, where you change the sign of the x value of the vertex (h) and keep the y component (k)
y=(x-8)^2 - 1
Expand that for x^2-16x+64-1
x^2-16x+63