Question 1015505: Ok. I don't know how else to write this problem because it
won't let me paste it here. It says: "If triangle KSD and
triangle WAT are similar, what is the measure of W?". In
triangle KSD it shows that angle K is the bottom of the
triangle, S is the top angle and D is the bottom right angle.
I don't know if this helps, but it also shows segments K to
S, S to D, and K to D in triangle WAT. It shows angle T as
The bottom left, angle W is the top of the triangle, and A
is the bottom right angle. It shows segment T to W, T to A
and W to A. Triangle KSD is lying on its side and triangle
WAT is standing up. Then it says to let K=16, D=34 and T=51.
What is the measure of W?
Answer by Edwin McCravy(20060)   (Show Source):
You can put this solution on YOUR website!
Something is wrong. If two triangles are similar,
the three angles of one are equal in measure to the
corresponding three angles of the other.
You have mentioned that two of the angles of ΔKSD are
∠K=16° and ∠D=34°. So that would mean that ∠S=130°,
because∠K+∠D+∠S=180°. That's because all the angles
of any triangle must total 180°.
But you also say that ∠T=51°. But since no angle of
ΔKSD can equal 51°, neither can any angle of ΔWAT
equal to 51°. Therefore ∠T=51° is impossible!
If you can explain the figure a little better, you
may do so in the thank-you note form below. I will
get back to you by email.
Edwin
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