SOLUTION: The perimeter of a rectangle is 90 yards. What is the perimeter of a rectangle that has twice the width and twice the height of the first rectangle?

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Question 1015119: The perimeter of a rectangle is 90 yards. What is the perimeter of a rectangle that has twice the width and twice the height of the first rectangle?

Answer by ayomidehos(1) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter = distance round an object
Going round a rectangle starting from any of its corners you get a perimeter equal to twice the width and twice the height of the rectangle.
So, in equation form the perimeter of a rectangle is:
perimeter = 2(width + height)
For the first rectangle;
90 = 2(width + height)
width + height = 90/2 = 45
Let us use w to represent its width and h to represent its height. Then
w + h = 45
For the second rectangle;
width = 2w
height = 2h
width + height = 2w + 2h
= 2(w +h)
= 2(45)
= 90
perimeter = 2(width + height)
= 2(90)
= 180
Therefore the perimeter of the second rectangle is 180 yards