SOLUTION: Can someone please help me with the below problem. I am totally lost....thank you. (2/3)(2x–4)=(1/2)(x+3)–4

Algebra ->  Inequalities -> SOLUTION: Can someone please help me with the below problem. I am totally lost....thank you. (2/3)(2x–4)=(1/2)(x+3)–4      Log On


   

Question 101497: Can someone please help me with the below problem. I am totally lost....thank you.

(2/3)(2x–4)=(1/2)(x+3)–4
Found 2 solutions by edjones, praseenakos@yahoo.com:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
(2/3)(2x – 4) = (1/2)(x + 3) – 4
Get rid of the fractions at you earliest convenience and your troubles are almost over.
4(2x-4)=3(x+3)-24 Multiply 6 times each side.
8x-16=3x+9-24 Multiply to eliminate parentheses.
8x-16=3x-15
5x=1 subtract 3x and add 16 to each side.
x=1/5 divide each side by 5
Check:
(2/3)(2/5 – 4) = (1/2)(1/5 + 3) – 4
4/15 - 8/3 = 1/10 + 3/2 - 4
8/30 - 80/30 = 3/30 + 45/30 - 120/30
72/30=72/30
That was a tough one!
Ed

Answer by praseenakos@yahoo.com(507) About Me  (Show Source):
You can put this solution on YOUR website!
Question:

Solve (2/3)(2x – 4) = (1/2)(x + 3) – 4

Answer:
(2/3)*(2x – 4) = (1/2)*(x + 3) – 4
MULTIPLY THROUGH OUT BY 6

==> +6%2A%282%2F3%29%2A%282x-4%29+=+6%2A%281%2F2%29%2A%28x%2B3%29+-+6%2A4


==> +2%2A+2+%2A%282x-4%29+=+3+%2A%28x%2B3%29+-+24+


==> +4%282x-4%29+=+3%28x%2B3%29+-24+


==> +4%2A2x+-+4+%2A4+=+3%2Ax+%2B+3%2A3+-24+

==> +8x+-+16+=+3x+%2B+9+-24+

==> +8x+-+16+=+3x++-15

Add 16 on both sides....



==> +8x+-+16+%2B+16+=+3x+-15+%2B+16

==> +8x++=+3x+%2B+1

subtract 3x from both sides....

==> +8x+-3x+=+3x+%2B+1-+3x

==> +5x+=+1

Divide both sides by 5

==> +5x%2F5+=+1%2F5


==> +x+=+1%2F5


==> x = 0.2

Which is the required solution.

Hope you found the explanation useful.

Regards.
Praseena.