Question 1014934: can you explain pythagorean theorem, step by step thanks
a=8
b=?
c=2rad97
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! the pythagorean theorem is normally stated as c^2 = a^2 + b^2
a is one leg of a right triangle.
b is the other leg of the right triangle.
c is the hyopenuse of the right triangle.
you are given that a = 8, b = ? c = 2rad97 which i assume is 2 * sqrt(97).
in the equation of c^2 = a^2 + b^2, you can solve for b to get:
b^2 = c^2 - a^2.
you know the value of a and you know the value of c, so you can replace a and c in the formula with those values to get:
b^2 = (2 * sqrt(97))^2 - 8^2
simplify this to get b^2 = 388 - 64
simplify further to get b^2 = 324
take the square root of both sides of this equation to get b = 18
your triangle now becomes:
a=8
b=18
c=2rad97
if this is true, then c^2 must be equal to a^2 + b^2 because pythagorus proved that it had to be way back in the days of ancient greece.
so (2 * sqrt(97))^2 must be equal to 8^2 + 18^2 if we calculated b correctly.
8^2 + 18^2 = 64 + 324 = 388
(2 * sqrt(97))^2 is also equal to 388.
the equation is confirmed to be true and your solution is that the value of b is 18.
here's a reference regarding the pythagorean theorem.
https://www.mathsisfun.com/pythagoras.html
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