SOLUTION: The perimeter of rectangle is 80 dm. The width is 1 more than one half the length. Find the length and width of the rectangle.

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Question 1014933: The perimeter of rectangle is 80 dm. The width is 1 more than one half the length. Find the length and width of the rectangle.
Answer by ikleyn(52775) About Me  (Show Source):
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The perimeter of rectangle is 80 dm. The width is 1 more than one half the length. Find the length and width of the rectangle.
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You need to solve this system of two equations

x + y = 40,
y - 1 = x%2F2,

where x is the length and y is the width.

Substitute y = 40 -x from (1) into (2).

You will get 

(40 - x) - 1 = x%2F2.

Multiply this equation by 2. You will get

80 - 2x - 2 = x,   or

78 + x + 2x = 3x.

Hence, x = 78%2F3 = 26 dm. It is the length.

The width is 40 - 26 = 14 dm.